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networking queestions Printed From: One Stop GATE Category: GATE Previous Years Test Papers - Discuss Here Forum Name: CS Papers Forum Discription: Computer Science Previous Year GATE Papers to can discussed here. URL: http://forum.onestopgate.com/forum_posts.asp?TID=122 Printed Date: 06Feb2025 at 9:19pm Topic: networking queestions Posted By: Adhiti Subject: networking queestions Date Posted: 02Feb2007 at 11:38am 1) Suppose you are designing a sliding window protocol for a 1 Mbps point-to-point link to a stationary satellite revolving around the earth at 3 * 10000 Km attitude. Assuming that each frame carries 1 Kb of data, what is the minimum number of bits you need for the sequence number when RWS = 1 (RWS = receiver window size) . a) 20 bits b) 32 bits c) 5 bits d) 16 bits 2) Compute approximate optimal window size when packet size is 53 bytes, propagation delay is 30 msec and bandwidth is 155 Mbps. a) 32,000 packets b) 12,000 packets c) 22,000 packets d) 42,000 packets Replies: Posted By: Alok Date Posted: 02Feb2007 at 3:59pm 1) Transmission time : 1Kb / 1Mbps = 2^10 / 10^6 Now propagation delay is : distance / signal speed here since sattelite communication is used signal speed is same as speed of light = 3 * 10^8 m/s Thus the RTT(round trip time) = 2 * propagation delay Thus total time it takes to complete transmission of one packet is TotalTime = Transmission time + RTT Since Sliding window protocol is used number of packets that can be transmitted in TotalTime= TotalTime / transmission time from the number of packets you can easily make out the number of bits required in sequence number 2^n >= Number of packets The same method can be used for second Question.

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