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unsolve question Printed From: One Stop GATE Category: GATE Previous Years Test Papers - Discuss Here Forum Name: CS Papers Forum Discription: Computer Science Previous Year GATE Papers to can discussed here. URL: http://forum.onestopgate.com/forum_posts.asp?TID=1391 Printed Date: 06Feb2025 at 4:54pm Topic: unsolve question Posted By: parvati123 Subject: unsolve question Date Posted: 04Aug2007 at 3:24am Consider a packet switching network with the packet size as 512 bits, message size as 1Kbits,propagation delay as 2sec/hop and the number of hops are 5. Then find the time required for the last it of the last packet to reach the receiver.(data transmission rate as 1 Kbit/sec) a.4058 sec b.2058sec c.3058 sec d.None my approach is this......... total message---1000 bits 1 pkt--------512 bits pkt2---------488 bits 1000 bit transmitted in 1 sec 512 ....................1/1000X512=.512 sec with delay 5X2=10 sec 488 ....................1/1000X488=.488 sec with delay 5X2=10 sec total time=(.512+10+.488+10)sec.... correct me plz. A system that uses a 2 level page table has 2^12 byte as page size and 32 bit virtual address.The 1st 8 bits of the address serve as the index into the 1st level page table. How many pages are there in virtual address??? a.2^10 b.2^12 c.2^20 d.None

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