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Author | Message |
Vijay
Newbie ![]() Joined: 03Feb2007 Online Status: Offline Posts: 1 |
![]() ![]() ![]() Posted: 03Feb2007 at 11:20am |
1) What is the minimum size of ROM required to store the complete
truth table of an 8 bit x 8 bit multiplier? A) 32K x 16 bits B) 64K x 16 bits C) 16K x 32 bits D) 64k x 32 bits 2) Which one of following statement is False ? A) TCP gurantees a minimum communication rate. B) TCP ensures in order delivery C) TCP reacts to congestion by reducing sender window size. D) TCP employs retransmission to compensate for packet loss. I know that option C and D are true, but confused between A and B. ![]() ![]() 3) In linear equations How can we know that it has infinite solution, Unique solution or No solution ?? e.g. x+y+z = 3 x+2y+3z = 4 2x+3y+4z = 7 Post Resume: Click here to Upload your Resume & Apply for Jobs |
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Kishor
Newbie ![]() Joined: 03Feb2007 Online Status: Offline Posts: 1 |
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2) A (There is no QoS ) provided by TCP
3) Solutions are Based on ranks of coeff matrix and augmented matrix. (also depends on number unknowns) _________________ Edited by Kishor - 07Feb2007 at 5:42pm |
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Kishor
Newbie ![]() Joined: 03Feb2007 Online Status: Offline Posts: 1 |
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1) What is the minimum size of ROM required to store the complete
truth table of an 8 bit x 8 bit multiplier? A) 32K x 16 bits B) 64K x 16 bits C) 16K x 32 bits D) 64k x 32 bits Solution: ====== Result of 2 8'bit values does not exceed 16bits.So, negelet the options A,D To lookup the result, ROM must be fed the 2 8'bit numbers as address, Hence the number of entries = 2^(8+8 )=2^16 = 64K So, the total size of the ROM is (64K x 16bits) |
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