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Topic: cos (x+y) = cos x cos y - sin x sin y | |
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parvati123
Newbie Joined: 04Aug2007 Online Status: Offline Posts: 1 |
Topic: cos (x+y) = cos x cos y - sin x sin y Posted: 04Aug2007 at 3:23am |
Can any body give complete explantaion / proof of above formula.
I need clear explanation... Pls help me.. Post Resume: Click here to Upload your Resume & Apply for Jobs |
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donesh1
Newbie Joined: 19Aug2007 Location: India Online Status: Offline Posts: 7 |
Posted: 19Aug2007 at 3:13am |
Sometimes we need to know the sine or cosine of the sum of two angles (in terms of the sines and cosines of the two angles). Here is a diagram which helps us find out what these are. First, we want to find Sin(x+y). Angles x and y are at point O. Assume that both are acute angles. B is a point on the outside ray of angle y. Draw BA perpendicular (at A) to the ray which is common to the two angles. Draw the other perpendicular lines (AD, BE, and AC) as shown. The second diagram shows how this would look if angles x and y are significantly larger. sin(x+y) = BE/OB = (BC+CE)/OB = (BC+AD)/OB = AD/OB + BC/OB = (AD/OB)×(OA/OA) + (BC/OB)×(BA/BA) = (AD/OA)×(OA/OB) + (BC/BA)×(BA/OB) sin(x+y) = sin x cos y + cos x sin y From this it also follows that sin(2x)=2 sin x cos x. The derivation for the cos(x+y) is similar. Using the same diagram: cos(x+y) = OE/OB = (OD-DE)/OB = (OD-AC)/OB = OD/OB - AC/OB = (OD/OB)×(OA/OA) - (AC/OB)×(BA/BA) = (OD/OA)×(OA/OB) - (AC/BA)×(BA/OB) cos(x+y) = cos x cos y - sin x sin y |
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Regards
Donesh |
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